IPL 2019: KXIP vs MI Kings XI wins toss opted to bowl against the Mumbai Indians
Here are the two playing XIs of the first match of the double-header.
Mumbai Indians: Quinton de Kock(W), Rohit Sharma(C), Suryakumar Yadav, Yuvraj Singh, Kieron Pollard, Hardik Pandya, Krunal Pandya, Mitchell McClenaghan, Mayank Markande, Jasprit Bumrah, Lasith Malinga
Kings XI Punjab: Lokesh Rahul(w), Chris Gayle, Mayank Agarwal, Sarfaraz Khan, David Miller, Mandeep Singh, Hardus Viljoen, Ravichandran Ashwin(c), Murugan Ashwin, Mohammed Shami, Andrew Tye
Kings XI Punjab captain R Ashwin has said the team will look to make use of the "easier batting conditions" in the evening. Meanwhile, Rohit Sharma says Mumbai Indians wanted to bat first anyway.
"We will be bowling first. We want to make conditions in the daylight and make use of the easier batting conditions later on when there could be some grease. We did win our games last time although it were just three matches, we also won the day game last season. So it's looking good," Ashwin said at the toss.
Rohit said: "We would have batted first anyway, so not really fussed. Having said that, we need to play good cricket. We were able to win our last game due to the bowling we had and it's about putting enough runs on the board for them."